Hacker Rank SQL

Employee Salaries Solution

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Write a query that prints a list of employee names (i.e.: the name attribute) for employees in Employee having a salary greater than $2000 per month who have been employees for less than 10 months. Sort your result by ascending employee_id.

Input Format

The Employee table containing employee data for a company is described as follows:

Column Type
employee_id Integer
name String
months Integer
salary Integer

where employee_id is an employee’s ID number, name is their name, months is the total number of months they’ve been working for the company, and salary is the their monthly salary.

Sample Input

employee_id name months salary
12228 Rose 15 1968
33645 Angela 1 3443
45692 Frank 17 1608
56118 Patrick 7 1345
59725 Lisa 11 2330
74197 Kimberly 16 4372
78454 Bonnie 8 1771
83565 Michael 6 2017
98607 Todd 5 3396
99989 Joe 9 3573

Sample Output



Angela has been an employee for 1 month and earns $3443 per month.
Michael has been an employee for 6 months and earns $2017 per month.
Todd has been an employee for 5 months and earns $3396 per month.
Joe has been an employee for 9 months and earns $3573 per month.
We order our output by ascending employee_id.

Solution – Employee Salaries Solution

MySQL Code
select name from employee 
where salary > 2000 and 
months < 10 order By employee_id;



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