Hacker Rank SQL

Top Earners Solution

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Problem

We define an employee’s total earnings to be their monthly salary x months worked, and the maximum total earnings to be the maximum total earnings for any employee in the Employee table. Write a query to find the maximum total earnings for all employees as well as the total number of employees who have maximum total earnings. Then print these values as 2 space-separated integers.

Input Format

The Employee table containing employee data for a company is described as follows:

Column Type
employee_id Integer
name String
months Integer
salary Integer

where employee_id is an employee’s ID number, name is their name, months is the total number of months they’ve been working for the company, and salary is the their monthly salary.

Sample Input

employee_id name months salary
12228 Rose 15 1968
33645 Angela 1 3443
45692 Frank 17 1608
56118 Patrick 7 1345
59725 Lisa 11 2330
74197 Kimberly 16 4372
78454 Bonnie 8 1771
83565 Michael 6 2017
98607 Todd 5 3396
99989 Joe 9 3573

Sample Output

69952 1

Explanation

The table and earnings data is depicted in the following diagram:

employee_id name months salary earnings
12228 Rose 15 1968 29520
33645 Angela 1 3443 3443
45692 Frank 17 1608 27336
56118 Patrick 7 1345 9415
59725 Lisa 11 2330 25630
74197 Kimberly 16 4372 69952
78454 Bonnie 8 1771 14168
83565 Michael 6 2017 12102
98607 Todd 5 3396 16980
99989 Joe 9 3573 32157

The maximum earnings value is 69952. The only employee with earnings=69952  is Kimberly, so we print the maximum earnings value (69952) and a count of the number of employees who have earned $69952 (which is 1) as two space-separated values.

 

Solution – Top Earners

MySQL Code
select max(months * salary), 
count(months * salary) from Employee where (months * salary) 
= (select max(months * salary) from Employee);

 

 

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