# Printing Pattern Using Loops in C HackerRank Solution

Hello Friends in this article i am gone to share Hackerrank C programming Solutions with you. | Printing Pattern Using Loops in C Hackerrank Solution.

Also visit: Bitwise Operators – Solution

### Objective

Print a pattern of numbers from to as shown below. Each of the numbers is separated by a single space.

```4 4 4 4 4 4 4
4 3 3 3 3 3 4
4 3 2 2 2 3 4
4 3 2 1 2 3 4
4 3 2 2 2 3 4
4 3 3 3 3 3 4
4 4 4 4 4 4 4 ```

### Input Format

The input will contain a single integer n.

1<n<1000

`2`

```2 2 2
2 1 2
2 2 2```

`5`

### Sample Output 1

```5 5 5 5 5 5 5 5 5
5 4 4 4 4 4 4 4 5
5 4 3 3 3 3 3 4 5
5 4 3 2 2 2 3 4 5
5 4 3 2 1 2 3 4 5
5 4 3 2 2 2 3 4 5
5 4 3 3 3 3 3 4 5
5 4 4 4 4 4 4 4 5
5 5 5 5 5 5 5 5 5```

`7`

### Sample Output 2

```7 7 7 7 7 7 7 7 7 7 7 7 7
7 6 6 6 6 6 6 6 6 6 6 6 7
7 6 5 5 5 5 5 5 5 5 5 6 7
7 6 5 4 4 4 4 4 4 4 5 6 7
7 6 5 4 3 3 3 3 3 4 5 6 7
7 6 5 4 3 2 2 2 3 4 5 6 7
7 6 5 4 3 2 1 2 3 4 5 6 7
7 6 5 4 3 2 2 2 3 4 5 6 7
7 6 5 4 3 3 3 3 3 4 5 6 7
7 6 5 4 4 4 4 4 4 4 5 6 7
7 6 5 5 5 5 5 5 5 5 5 6 7
7 6 6 6 6 6 6 6 6 6 6 6 7
7 7 7 7 7 7 7 7 7 7 7 7 7```

Hackerrank  C programming Solutions

## Printing Pattern Using Loops in C Hackerrank Solution -1

```#include <stdio.h>

int main()
{

int n;
scanf("%d", &n);

// Complete the code to print the pattern.

int len = n*2 - 1;
for(int i=0;i<len;i++){
for(int j=0;j<len;j++){
int min = i < j ? i : j;
min = min < len-i ? min : len-i-1;
min = min < len-j-1 ? min : len-j-1;
printf("%d ", n-min);
}
printf("\n");
}
return 0;
}```

### Printing Pattern Using Loops in C Hackerrank Solution -2

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main()
{
int n;
scanf(“%d”, &n);

for(int i = n; i >= 1; i–){
for(int j = n; j > i; j–)
printf(“%d “, j);
for(int j = 1; j <= 2 * i – 1; j++)
printf(“%d “, i);
for(int j = i + 1; j <= n; j++)
printf(“%d “, j);
printf(“\n”);
}

for(int i = 1; i < n; i++){
for(int j = n; j > i; j–)
printf(“%d “, j);
for(int j = 1; j <= 2 * i – 1; j++)
printf(“%d “, i + 1);
for(int j = i + 1; j <= n; j++)
printf(“%d “, j);
printf(“\n”);
}

return 0;
}

### Printing Pattern Using Loops in C Hackerrank Solution -3

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main()
{
int n;
scanf(“%d”, &n);

for(int i = n; i >= 1; i–){
for(int j = n; j > i; j–)
printf(“%d “, j);
for(int j = 1; j <= 2 * i – 1; j++)
printf(“%d “, i);
for(int j = i + 1; j <= n; j++)
printf(“%d “, j);
printf(“\n”);
}

for(int i = 1; i < n; i++){
for(int j = n; j > i; j–)
printf(“%d “, j);
for(int j = 1; j <= 2 * i – 1; j++)
printf(“%d “, i + 1);
for(int j = i + 1; j <= n; j++)
printf(“%d “, j);
printf(“\n”);
}

return 0;
}