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Printing Pattern Using Loops in C HackerRank Solution

Hello Friends in this article i am gone to share Hackerrank C programming Solutions with you. | Printing Pattern Using Loops in C Hackerrank Solution.

Objective

Print a pattern of numbers from to as shown below. Each of the numbers is separated by a single space.

4 4 4 4 4 4 4 
4 3 3 3 3 3 4 
4 3 2 2 2 3 4 
4 3 2 1 2 3 4 
4 3 2 2 2 3 4 
4 3 3 3 3 3 4 
4 4 4 4 4 4 4 

Input Format

The input will contain a single integer n.

Constraints

1<n<1000

Sample Input 0

2

Sample Output 0

2 2 2
2 1 2
2 2 2

Sample Input 1

5

Sample Output 1

5 5 5 5 5 5 5 5 5 
5 4 4 4 4 4 4 4 5 
5 4 3 3 3 3 3 4 5 
5 4 3 2 2 2 3 4 5 
5 4 3 2 1 2 3 4 5 
5 4 3 2 2 2 3 4 5 
5 4 3 3 3 3 3 4 5 
5 4 4 4 4 4 4 4 5 
5 5 5 5 5 5 5 5 5

Sample Input 2

7

Sample Output 2

7 7 7 7 7 7 7 7 7 7 7 7 7 
7 6 6 6 6 6 6 6 6 6 6 6 7 
7 6 5 5 5 5 5 5 5 5 5 6 7 
7 6 5 4 4 4 4 4 4 4 5 6 7 
7 6 5 4 3 3 3 3 3 4 5 6 7 
7 6 5 4 3 2 2 2 3 4 5 6 7 
7 6 5 4 3 2 1 2 3 4 5 6 7 
7 6 5 4 3 2 2 2 3 4 5 6 7 
7 6 5 4 3 3 3 3 3 4 5 6 7 
7 6 5 4 4 4 4 4 4 4 5 6 7 
7 6 5 5 5 5 5 5 5 5 5 6 7 
7 6 6 6 6 6 6 6 6 6 6 6 7 
7 7 7 7 7 7 7 7 7 7 7 7 7

 


Hackerrank  C programming Solutions

Printing Pattern Using Loops in C Hackerrank Solution -1

#include <stdio.h>

int main() 
{

    int n;
    scanf("%d", &n);

// Complete the code to print the pattern.

    int len = n*2 - 1;
    for(int i=0;i<len;i++){
        for(int j=0;j<len;j++){
            int min = i < j ? i : j;
            min = min < len-i ? min : len-i-1;
            min = min < len-j-1 ? min : len-j-1;
            printf("%d ", n-min);
        }
        printf("\n");
    }
    return 0;
}

 

Printing Pattern Using Loops in C Hackerrank Solution -2

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main()
{
int n;
scanf(“%d”, &n);

for(int i = n; i >= 1; i–){
for(int j = n; j > i; j–)
printf(“%d “, j);
for(int j = 1; j <= 2 * i – 1; j++)
printf(“%d “, i);
for(int j = i + 1; j <= n; j++)
printf(“%d “, j);
printf(“\n”);
}

for(int i = 1; i < n; i++){
for(int j = n; j > i; j–)
printf(“%d “, j);
for(int j = 1; j <= 2 * i – 1; j++)
printf(“%d “, i + 1);
for(int j = i + 1; j <= n; j++)
printf(“%d “, j);
printf(“\n”);
}

return 0;
}


Printing Pattern Using Loops in C Hackerrank Solution -3

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main()
{
int n;
scanf(“%d”, &n);

for(int i = n; i >= 1; i–){
for(int j = n; j > i; j–)
printf(“%d “, j);
for(int j = 1; j <= 2 * i – 1; j++)
printf(“%d “, i);
for(int j = i + 1; j <= n; j++)
printf(“%d “, j);
printf(“\n”);
}

for(int i = 1; i < n; i++){
for(int j = n; j > i; j–)
printf(“%d “, j);
for(int j = 1; j <= 2 * i – 1; j++)
printf(“%d “, i + 1);
for(int j = i + 1; j <= n; j++)
printf(“%d “, j);
printf(“\n”);
}

return 0;
}


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